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要使除数最小被除数是多少怎么算
更新时间: 2021-06-16 02:59:57  

1、A÷B=121…5中,要使除数最小,被除数是:731;解析:根据在有余数的除法算式中,除数一定大于余数,已知余数是5,除数最小就是:5+1=6。

2、根据:被除数=商×除数+余数,就可得出最小的被除数,列式为:5+1=6;121×6+5=726+5=731,验算:731÷6=121……5。

关键词: 除数 被除数 多少 怎么

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