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2%戊二醛怎么兑成0.78%
更新时间: 2021-01-12 20:01:06  

1、在原消毒水中加入1.56倍质量的水。

2、根据溶液的相关知识,溶剂质量=溶液质量*浓度,设溶液的质量为a,需要在原溶液中加入质量为X的水,则根据题设有:

2%a/(a+X)=0.78%

即2%a=0.78%a+0.78%X

合并同类项得0.78%X=1.22%a

将系数化为1,则X=1.56a,即需要在原来的消毒水中加入1.56倍的水。

关键词: 怎么

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